I was wondering if this is possible.
我有一个自定义的post类型调用项目，它显示一个带有下拉菜单的metabox。在这个下拉菜单中，我列出了几个选项：草稿、打开、挂起和完成。一旦您选择了您想要的字段，我希望只有在所选作者登录时，才能够在前端显示该选项的帖子计数。
例如，作者A在4篇不同的帖子上选择完成4次。因此，当作者A登录到该站点时，他会在前端看到一个数字4，并填写了单词。
这是我用来显示下拉菜单的内容
array(
\'name\' => __( \'Project Status\', \'projects\' ),
\'desc\' => __( \'\', \'projects\' ),
\'id\' => $prefix . \'project_select\',
\'type\' => \'select\',
\'options\' => array(
\'Select a Status\' => __( \'Select a Status\', \'projects\' ),
\'Draft\' => __( \'Draft\', \'projects\' ),
\'Open\' => __( \'Open\', \'projects\' ),
\'Pending\' => __( \'Pending\', \'projects\' ),
\'Closed\' => __( \'Closed\', \'projects\' ),
\'Completed\' => __( \'Completed\', \'projects\' ),
),
最合适的回答,由SO网友:Adam Mo. 整理而成
请尝试以下代码：
function postsCount($meta_value) {
$args = array(
\'numberposts\' => -1,
\'post_type\' => \'custom_post_type\', // set you custom post type
\'meta_key\' => \'project_select\',
\'meta_value\' => $meta_value,
);
$my_posts = get_posts( $args );
$postsCount = count($my_posts);
return $postsCount;
}
if ( is_user_logged_in() ) {
echo postsCount(\'Draft\');
echo postsCount(\'Completed\');
}
或者，如果您想通过较少的代码获得所有计数，请尝试以下操作：
function postsCount() {
if ( !is_user_logged_in() ) {
return;
}
$meta_value_array = array( \'Draft\', \'Open\', \'Pending\', \'Closed\', \'Completed\');
$postsCount = \'<ul>\';
foreach ($meta_value_array as $meta_value) {
$args = array(
\'numberposts\' => -1,
\'post_type\' => \'custom_post_type\', // set you custom post type
\'meta_key\' => \'project_select\',
\'meta_value\' => $meta_value,
);
$my_posts = get_posts( $args );
$postsCount = count($my_posts);
$postsCount .= \'<li>\' .$meta_value. \' \' .$postsCount. \'</li>\';
}
$postsCount .= \'</ul>\';
return $postsCount;
}
echo postsCount();
