Ajax button not working

因此，我试图在wp中创建一个follow按钮，但由于某些原因，ajax按钮不能正常工作。下面是应该发生的事情的步骤

用户单击followbtn，Ajax转到$\\u POST action，该操作=follow，php运行wp\\u set\\u object\\u terms（$user\\u id，$author\\u id，\'follow\'，true）

完成后，如果数据=ok，则函数echo为“ok”

重新加载页面。由于某种原因，php没有执行，页面也没有重新加载。

add_action( \'wp_ajax_nopriv_jk-author-follow\', \'jk_author_follow\' );
add_action( \'wp_ajax_jk-author-follow\', \'jk_author_follow\' );
function jk_author_follow() {
$nonce = $_POST[\'nonce\'];
if ( ! wp_verify_nonce( $nonce, \'ajax-nonce\' ) )
    die ( \'Nope!\' );

if($_POST[\'action\'] == "follow") {

$author_id = get_the_author_meta( \'nickname\' ); // get authors name    
$termId = get_term_by( \'slug\', $author_id, \'follow\' ); // get the term id from author
$termId = $termId->term_id;
$followers = get_objects_in_term( $termId, \'follow\' ); // count followers in author term
$author_follow_count = count( $followers );

if ( is_user_logged_in() ) { // user is logged in
    $user_id = get_current_user_id(); // current user
    wp_set_object_terms( $user_id, $author_id, \'follow\', true ); // Follow the author
    echo "ok"; 
   } 
  }
 }
exit;
}

前端按钮

function getAuthorFollowLink( $author_id ) {
$author = get_the_author_meta( \'nickname\' );
$user_ID = get_current_user_id();
$termId = get_term_by( \'slug\', $author, \'follow\' ); // get the term id from author
$termId = $termId->term_id;
$followers = get_objects_in_term( $termId, \'follow\' ); // count followers in author term
$count = count( $followers );
$output = \'<a href="#" id="followbtn">Folllow&nbsp;\'.$count.\'</a>\';
return $output;
}

js公司

$(function(){
$(\'#followbtn\').on(\'click\', function(e){
e.preventDefault();
$(\'#followbtn\').fadeOut(300);

$.ajax({
  url: ajax_var.url,
  type: \'post\',
  data: {\'action\': \'follow\'},
  success: function(data, status) {
    if(data == "ok") {
        location.reload();
    }
  },
  error: function(xhr, desc, err) {
    console.log(xhr);
    console.log("Details: " + desc + "\\nError:" + err);
  }
   }); // end ajax call
 });
});

var data = { action: \'jk-author-follow\', // Look Ma\' I talk to your PHP! :) // ... // here you can add any other custom vars you need to pass to the PHP handler }; $.post(ajax_var.url, data, function(response){ if( typeof(console) == \'object\' ) console.log( response ); });

没有插件的AJAX登录不起作用。在将操作添加到unction.php时

我使用的是wordpress ajax登录，没有插件。我希望不允许用户在登录后访问WordPress配置文件，因为我在链接中设计了一个特定的配置文件：http://www.domain.com/profile. 这就是我使用以下代码的原因。当我向函数添加以下代码时。php。AJAX登录不起作用。 // Redirect user to profile.php page add_action(\'init\' , \'prevent_profile_access\'); function

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没有插件的AJAX登录不起作用。在将操作添加到unction.php时