我正在尝试为外部链接创建自己的重定向页面。

My target

我的目标是，当用户打开链接时www.mysite.com/wp/GoTo/?URL=www.google.com, 浏览器打开页面www.google.com

What I have done

我保存了以下内容GoTo.php 文件夹中的文件wp-content/themes/theme-name/:

<?php


/*
Template Name: GoTo
*/

/**
 * The template for displaying all pages.
 *
 * This is the template that displays all pages by default.
 * Please note that this is the WordPress construct of pages
 * and that other \'pages\' on your WordPress site will use a
 * different template.
 *
 * @package theme-name
 */

$url = $_GET["URL"];

// Remove all illegal characters from a url
$url = filter_var($url, FILTER_SANITIZE_URL);

if (filter_var($url, FILTER_VALIDATE_URL) !== true) {
    header("location: " . $url);
    exit;
} else {
echo("$url is not a valid URL");
}
?>

然后我创建了一个带有URL的页面www.mysite.com/wp/GoTo/ 带模板GoTo.

目前：

如果我打开www.mysite.com/wp/GoTo/?URL=xyz 我收到404错误（如果我打开www.mysite.com/wp/GoTo/?URL=www.google.com 我得到一个404错误（而不是打开google.com）如何修复此问题？不幸的是，我不能直接引用php页面。换句话说，我不能在浏览器中写字www.mysite.com/wp/wp-content/themes/theme-name/Z_GoTo.php?URL=www.google.com, 因为mod rewrite包含反对它的规则。

Disclamer

我知道WP中有几个关于重定向的问题，但没有一个是关于我这样的情况。

filter_var($url, FILTER_VALIDATE_URL) !== true

filter_var($url, FILTER_VALIDATE_URL)

$url = $_GET["URL"];

// Remove all illegal characters from a url
$url = filter_var($url, FILTER_SANITIZE_URL);

if (filter_var($url, FILTER_VALIDATE_URL)) {
    header("location: " . $url);
    exit;
} else {
    echo("$url is not a valid URL");
}

// Has the protocol; this would always redirect to http://www.google.com
header( \'Location: http://www.google.com\' );
exit;

// Protocol not specified; redirects to a URL on your site. For example,
// if you\'re on http://your-site.com/path, then you\'d be redirected to
// http://your-site.com/path/www.google.com
header( \'Location: www.google.com\' );
exit;