如何确定搜索查询中的结果是帖子还是页面？

我认为这个问题在互联网上很容易找到……然而，似乎以前没有人遇到过这个问题。

输入搜索词时，列出搜索查询没有问题，I needed posts and pages to be differentiated in a way. 例如：我希望作为帖子（文章）的结果显示作者、阅读时间和发布日期，但我不希望这些元显示在作为页面的结果上。

以下是代码：

    $paged = ( get_query_var( \'paged\' ) ) ? get_query_var( \'paged\' ) : 1;
    $searchArgs = array(
    \'s\' => $s,
    \'paged\' => $paged,
    \'showposts\' => -1,
    );
    $searchQuery = new WP_Query( $searchArgs );
    if ( $searchQuery->have_posts() ) :
    echo \'<h2>\';
    echo \'result: \'.search_query();
    echo \'</h2>\';
    while ( $searchQuery->have_posts() ) : $searchQuery->the_post();
      echo \'link: \'.get_the_permalink();
      echo \'Title: \'.get_the_title();
      echo \'Post Summary: \'.get_the_excerpt();
      $how = ( is_single() ) ? \'this result is a post\' : \'your method did not work\'; //always return false
      $how = ( is_page() ) ? \'this result is a page\' : \'your method did not work\'; //always return false.
      echo \'Post Type: \'.$how; // <------ How to do?
      //***Problem***: is_single() or is_page() does not work, by the way (both return false).
      //I\'ve crossed-checked that the results are actually either a post or a page.
    endwhile;
    endif;

if ( function_exists(\'custom_pagination\') ) {
      custom_pagination($searchQuery->max_num_pages,"",$paged);
    }

所以我的问题是，is\\u page（）和is\\u single（）在我所做的搜索查询中不起作用。

你如何正确地做到这一点？

function xyz_get_post_type_name() { $wp_type = get_post_type( get_the_ID() ); switch ($wp_type) { case \'post\' : $type_name = \'Article\'; break; case \'page\' : $type_name = \'Web Page\'; break; case \'quote\' : $type_name = \'Testimonial\'; break; case \'post_tag\' : $type_name = \'Topic\'; break; default : $type_name = ucfirst($wp_type); break; } // END switch return $type_name; } // END xyz_get_post_type_name()

$queryIsPost = (get_post_type() === \'post\') ? true : false; //the solution $queryIsPage = (get_post_type() === \'page\') ? true : false; //the solution $searchArgs = array( \'s\' => $s, \'paged\' => $paged, \'showposts\' => -1, ); $searchQuery = new WP_Query( $searchArgs ); if ( $searchQuery->have_posts() ) : echo \'<h2>\'; echo \'result: \'.search_query(); echo \'</h2>\'; while ( $searchQuery->have_posts() ) : $searchQuery->the_post(); echo \'link: \'.get_the_permalink(); echo \'Title: \'.get_the_title(); echo \'Post Summary: \'.get_the_excerpt(); if ($queryIsPost) { $thePostType = "Post"; } elseif ($queryIsPage) { $thePostType = "Page"; } else { $thePostType = "Error. Not determined"; } echo \'Post Type: \'.$thePostType; endwhile; endif;

如何将变量传递给Get_Search_Form()？

是否可以将变量传递给get_search_form()? 我在两个地方使用它：一个在标题中，另一个在内容的搜索页面上。后者必须具有附加类，例如。search--full. 我试着用is_search() 但尽管它在其他页面上运行良好，但在搜索页面上，两种表单都有search--full 班

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如何将变量传递给Get_Search_Form()？